4x^2-8x-86=-8

Solution for 4x^2-8x-86=-8 equation:

4x^2-8x-86=-8

We move all terms to the left:

4x^2-8x-86-(-8)=0

We add all the numbers together, and all the variables

4x^2-8x-78=0

a = 4; b = -8; c = -78;
Δ = b2-4ac
Δ = -82-4·4·(-78)
Δ = 1312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1312}=\sqrt{16*82}=\sqrt{16}*\sqrt{82}=4\sqrt{82}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{82}}{2*4}=\frac{8-4\sqrt{82}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{82}}{2*4}=\frac{8+4\sqrt{82}}{8}
$